Integermania - Digits of Pi

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Integermania!

Digits of Pi

This Integermania problem is a bit different than the others, as different digits will be used to create each of the integers. In particular, the following two ADDITIONAL rules must be met:

To create the integer $N$, you must use the five digits that appear from the $(5N-4)$th to $(5N)$th place of the decimal expansion of $\pi$.
The digits used to create $N$ must be in the same order as they occur in the decimal expansion of $\pi$.

Your solutions will be assigned an exquisiteness level.

We use MathJax

Use the online submissions page to get your Integermania solutions posted here! Five "new" or "improved" solutions per person per month are accepted.

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									0 (1.0) $0 + 0 + 0 + 0 \times 3.$ Steve Wilson, 3/23 Lawrence, KS
1 (1.0) $\dfrac{1 \times 4 + 1 \times 5}{9}$ Steve Wilson, 3/23 Lawrence, KS	2 (1.0) $\dfrac{2 \times 6 - 5 + 3}{5}$ Dana Reigle, 3/23 Lewisburg, PA	3 (1.0) $(8 + 9 - 7 - 9) \times 3$ Dana Reigle, 3/23 Lewisburg, PA	4 (1.0) $2 \times 3 + 8 - 4 - 6$ Dana Reigle, 3/23 Lewisburg, PA	5 (1.0) $2 - (6 - 4 - 3) \times 3$ Dana Reigle, 3/23 Lewisburg, PA	6 (1.0) $(8 + 3) \times 2 - 7 - 9$ Dana Reigle, 3/23 Lewisburg, PA	7 (1.0) $5 + 0 + 2 + 8 - 8$ Steve Wilson, 3/23 Lawrence, KS	8 (1.0) $4 + 1 + 9 - 7 + 1$ Steve Wilson, 3/23 Lawrence, KS	9 (1.0) $6 + \dfrac93 + 9 - 9$ Steve Wilson, 3/23 Lawrence, KS	10 (1.0) $(3 + 7) + (5 + 1) \times 0$ Jacob Heasley, 3/23 York, PA
11 (1.0) $\dfrac{5 \times 8}{2} + 0 - 9$ Jacob Heasley, 3/23 York, PA	12 (1.0) $7 + 4 + 9 - 4 - 4$ Jacob Heasley, 3/23 York, PA	13 (1.0) $5 + 9 + 2 - 3 + 0$ Jacob Heasley, 3/23 York, PA	14 (1.0) $\dfrac{7}{8 \times 1 - 6} \times 4$ Jacob Heasley, 3/23 York, PA

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